Solve Quadratic equations x^2+x-12=0 ...

Consider the form x2+bx+c x 2 + b x + c . Find a pair of integers whose product is c c and whose sum is b b . In this case, whose product is −12 - 12 and whose ...

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Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, ...

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If x(-2) (x-3) =-12, what is the value of x? => -2x(x-3)=-12.

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Therefore, the factors of x2−x−12 are (x−4) and (x+3). Set each factor equal to 0 and solve for x:x−4=0,x=4, and x+3=0,x=−3; x2−x=12 when x equals 4 or −3.

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So, the factorisation of x2-x-12 = (x-4)(x+3).To check if you factorised the equation correctly, we can expand the brackets to get: x2-4x+3x-12 which = x2-x-12 ...

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Move all terms to one side. x 2 − x − 12 = 0 {x}^{2}-x-12=0 x2 ...

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Y=x^2-x-12=0 Y= (x+3)(x-4) in the factored form And the solution, Either x+3=0, x=-3 and/or x-4=0, x=4 hence, x=-3, +4

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Tiger shows you, step by step, how to solve YOUR Quadratic Equations x^2+x-12=0 by Completing the Square, Quadratic formula or, whenever possible, ...

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